Work force x displacement or distance between

Therefore, work need only be computed for the gravitational forces acting on the bodies. Another example is the centripetal force exerted inwards by a string on a ball in uniform circular motion sideways constrains the ball to circular motion restricting its movement away from the centre of the circle. This force does zero work because it is perpendicular to the velocity of the ball.

It can change the direction of motion but never change the speed. This scalar product of force and velocity is known as instantaneous power. It's not force times distance. But returning to your original question I believe you are having difficulty differentiating the terms distance and displacement. Distance is an absolute measure between two points in space. Displacement is a relative measure of distance which can turn out to be zero if you start and end at the same place.

When you raise a weight 10 ft high and lower it to it's original height the net work done ON the object is zero since the displacement is zero. That's because when you return the object to the original position its gained potential energy that was stored 'in' the object is being spent. The object is now doing work on whatever opposing force is doing the lowering.

The formula can be used when the restoring force is other than a gravitational field.

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Work done on an object along a given direction of motion is equal to the force times the displacement times the cosine of the angle. Is work force x distance? In words: Work is equal to the force that is exerted times the distance over which it is exerted. Is force equal to distance? Work is a measure of the energy expended in applying a force to move an object. Can force act even at a distance? Electric Forces as Non-Contact Forces Gravitational forces are action-at-a-distance forces that act between two objects even when they are held some distance apart.

If you watch a roller coaster car move along its course, then you are witnessing an action-at-a-distance. What is an example of force at a distance? What are two examples of action-at-a-distance forces? Contact Forces. What is the difference between work and force?

If work is done, then the kinetic energy of an object changes. Why is work important in physics? Physics work: Work is the product of force and distance, that is, it is the amount of energy required to move something a certain distance against a particular force. More precisely, it is an integral that allows you to relate force and energy in a particular way and can be quite sophisticated mathematically. What is the difference between work and negative work?

Both positive work and negative work have meaning: Positive work follows when the force has a component parallel to the displacement. Positive work adds energy to a system. Negative work follows when the force has a component opposite or against the displacement. Is work same as energy? In physics, work is the energy transferred to or from an object via the application of force along a displacement.

Work transfers energy from one place to another, or one form to another. The SI unit of work is the joule J , the same unit as for energy. How is the relationship between force and motion explained? When does force change the direction of motion? When force is applied on an object in an angle different to its direction of motion, it causes the object to change motion. Almost every ball game uses this principle.

The speed can be maintained if the force is applied in a perpendicular angle but the velocity will change Force and Motion Formula Who was the first person to discover the relationship between force and motion? The first person to discover the relationship between motion and force was Sir Isaac Newton.

From his studies in force and law of motion, which we arrive at the following conditions: Force is applied to a body at rest, it begins to move and accelerates.

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The expended work is what's being spent in maintaining the isometric tension in your muscles. It's not force times distance. But returning to your original question I believe you are having difficulty differentiating the terms distance and displacement. Distance is an absolute measure between two points in space. Displacement is a relative measure of distance which can turn out to be zero if you start and end at the same place. When you raise a weight 10 ft high and lower it to it's original height the net work done ON the object is zero since the displacement is zero.

That's because when you return the object to the original position its gained potential energy that was stored 'in' the object is being spent. The object is now doing work on whatever opposing force is doing the lowering. Moving 10 m one way, you do work. Moving back 10 m, you do more work. Solution 2 If you 'carry' an object 10 meters in one direction then return it back 10 meters from where you started the work done on the object is not the force you expended times distance walked.

The formula you write is often misunderstood and misused. In your example, when you lift the object in a gravitational field, the work being done on the object is its weight force times the vertical distance it's lifted. When you walk ten feet in one direction, then back there is zero work done on the object assuming you held the object at the same vertical position. Once you return to your point of origin and lower the object the object is now doing work on your muscles.

The process of carrying the object horizontally is much more complicated when trying to figure out how much work is being expended. The expended work is what's being spent in maintaining the isometric tension in your muscles. It's not force times distance. But returning to your original question I believe you are having difficulty differentiating the terms distance and displacement. Distance is an absolute measure between two points in space. Displacement is a relative measure of distance which can turn out to be zero if you start and end at the same place.

When you raise a weight 10 ft high and lower it to it's original height the net work done ON the object is zero since the displacement is zero.